Interview Questions from PrepBytes with Answers.

Question By PrepBytes

Answer is ::

Program ::

Using Scanner Class :

import java.io.*; //Input Output Package imported

import java.util.*; //Util Package imported

public class PrepBytes1

{

public static void main(String args[])

{

int i,flag; //Required variables are declared

char ch;

Scanner in = new Scanner(System.in); //object of Scanner Class is created

//for taking inputs from User. Present in java.util package.

System.out.println("Enter the Size of an Array ::");

int n = in.nextInt(); //nextInt() method is present in Scanner Class

//used to get Integer values from User.

int A[] = new int[n]; //Array of integer is created of size 'n'

System.out.println("Enter Sorted Array Elements ::");

for(i=0;i<n;i++)

{

A[i]=in.nextInt();

} //Taking Sorted array from user and storing them

//into array.

do

{

System.out.println("Enter the Element to be Searched ::");

int key = in.nextInt();

flag=0; //flag is used as a indicator if the element is

//found or not

for(i=0;i<n;i++)

{

if(key==A[i]) //Comparison is made with key element and

//element stored in array one by one.

{

flag=1; //if found flag is updated to 1 and loop is broken

break;

}

}

if(flag == 1) //result as per flag value is displayed on screen.

{

System.out.println("Element Found");

}

else

{

System.out.println("Element Not Found");

}

System.out.println("Want to Continue (y/n)"); //message to ask whether

//we want to perform same action again is given to console.

ch = in.next().charAt(0);

}while(ch=='y'||ch=='Y');

}

}

Output ::

Enter the Size of an Array ::

5

Enter Sorted Array Elements ::

1

2

3

4

5

Enter the Element to be Searched ::

5

Element Found

Want to Continue (y/n)

y

Enter the Element to be Searched ::

9

Element Not Found

Want to Continue (y/n)

n

Hope u Understood the concept. Happy Learning.