Interview Question from PrepBytes with Answers.

Question by PrepBytes

Answer is ::

Program ::

Using BufferedReader Class

import java.io.*; //Input-Output package imported

public class PrepBytes1

{

public static void main(String args[]) throws IOException // throws is a

//keyword in Java which is used in the signature of method to indicate

//that this method might throw one of the listed type exceptions .

{

int i,flag;

char ch;

BufferedReader buf = new BufferedReader(new InputStreamReader(System.in)); //BufferedReader reads from an

//InputStreamReader( reads bytes from System.in ) that reads from

//System.in( is an InputStream ).

System.out.println("Enter the Size of an Array ::");

int n = Integer.parseInt(buf.readLine());

int A[] = new int[n];

System.out.println("Enter Sorted Array Elements ::");

for(i=0;i<n;i++)

{

A[i]=Integer.parseInt(buf.readLine()); //parseInt method is used to

//convert the String value taken from keyboard to Integer.

}

do

{

System.out.println("Enter the Element to be Searched ::");

int key = Integer.parseInt(buf.readLine());

flag=0;

for(i=0;i<n;i++)

{

if(key==A[i])

{

flag=1;

break;

}

}

if(flag == 1)

{

System.out.println("Element Found");

}

else

{

System.out.println("Element Not Found");

}

System.out.println("Want to Continue (y/n)");

ch = buf.readLine().charAt(0);

}while(ch=='y'||ch=='Y');

}

}

Output ::

Enter the Size of an Array ::

5

Enter Sorted Array Elements ::

1

2

3

4

5

Enter the Element to be Searched ::

2

Element Found

Want to Continue (y/n)

y

Enter the Element to be Searched ::

9

Element Not Found

Want to Continue (y/n)

n

Hope u Understood the concept. Happy Learning.